Doesn't seem like there is much to do. If x = log3 (2), then 3^x = 2. that to me seems to be rewritten in terms of x. If you wanted to solve for an actual number, calculators generally use log10. So, log10 (3^x) = log10 (2), then x log10 (3) = log10 (2), then x = log10 (2) / log10 (3). That you can do in a calculator easily. For the other, the same ideas results in 3^y = 10, and in terms of log10, you get y = log10 (10) / log10 (3). Simplifying to y = 1 / log10 (3). Maybe I'm missing something, but 3^x = 2 and 3^y = 10 seems like all you need to do.