morningsun

Sorry, that equation wasn't simplified. Here you go:

1/((2/s)*sin(360/2n)) or ((2/s*sin(360/2n))^-1.

VM you when I am ready.

oops sorry I was busy >_<

Yes I saw the PS update and there are a ton of new useful features too.

K

I want to see you fight Magcargo 2

I just created a new equation:
4^(-1)*(1/((1/2s)*sin(360/2n))) lets you find the radius of the circle of a regular, circumscribed polygon given s equals the side length of each side and n equals the number of sides. I don't know if anybody else has used this before. If it can be simplified, let me know. It really does work.

oops wrong place to post :I

morningsun vs. Magcargo 2

This is your opponent for the next round. Good luck!

Whenever you're on, catch me on PS. I have mixed news.

Each one continues to get larger and large until one is so big that it overloads the software and forced it to exit out of the program. They just keep getting bigger.