Question.

Jigglychu

What is the formula for raising a stat one or two stages, like Dragon Dance, Swords Dance, Iron Defense, Agility, Amnesia, etc. I know i've seen it here before but I can't remember where.
 
Not entirely true, it goes:
2/2 --> 3/2 --> 4/2 --> 5/2 --> etc.

Or for -1, -2, -3 etc it goes:
2/2 --> 2/3 --> 2/4 --> etc.

Or for an easy formula:
((2+|x|)/2)^f(x)

where f(x) = 1 if x is positive and -1 if x is negative.
 
Surgo - surely f is not a function of x, and is instead +1 if the stat is being boosted and -1 if the stat is being reduced, with x being the number of boosts/reductions?

That way you don't get problems trying to put x = -2 or something..
 
That's what I said...
"where f(x) = 1 if x is positive and -1 if x is negative."

I did notice and fix a different problem though.
 
DMFG said:
Surgo - surely f is not a function of x, and is instead +1 if the stat is being boosted and -1 if the stat is being reduced, with x being the number of boosts/reductions?

That way you don't get problems trying to put x = -2 or something..
Click to expand...

ummm |x| = Absolute value of x

if it is -2 or 2 -> it becomes 2.
So i don't see where the problem occurs, Surgo's forumla works.
 
Basically:

-6 Levels = * 0.25
-5 Levels = * 0.29
-4 Levels = * 0.33
-3 Levels = * 0.40
-2 Levels = * 0.50
-1 Levels = * 0.66
0 Levels = * 1.00
+1 Levels = * 1.50
+2 Levels = * 2.00
+3 Levels = * 2.50
+4 Levels = * 3.00
+5 Levels = * 3.50
+6 Levels = * 4.00
 
Surgo's formula works because he sneak edited it to make it work :p there was no modulus sign when I replied earlier
 
Surgo's f(x) is sometimes called sign(x) or sgn(x).

sign(x) = 1, if x>0
sign(x) = -1, if x<0
sign(x) = 0, if x=0
 
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