The ratio of the intensities at minima to the maxima in the Young's double slit experiment is 9 : 25. Find the ratio of the widths of the two slits.

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#### Solution

Let w, a,I represent the slit width, amplitude and intensity.

`I_(min)/I_(max)=(a_1-a_2)^2/(a_1+a_2)^2=9/25`

`((a_1-a_2))/((a_1+a_2))=3/5`

Or

`a_1/a_2=4/1`

and

`w_1/w_2=(a_2)^2/(a_2)^2=16/1`

Concept: Interference of Light Waves and Young’S Experiment

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