I spent hours doing this with Espurr.

- Thread starter Reikai
- Start date

I spent hours doing this with Espurr.

I'm at the stage where I have a 31/x/31/31/31/x Rotom of an unwanted nature. I have a Bold Ditto with 31s in HP and Spe. Should I slap on an Everstone and Destiny Knot at this stage, or use Knot + Power Anket to get the 31/x/31/31/31/31 unwanted nature Rotom, then breed with the Bold Ditto with everstone?

I'm at the stage where I have a 31/x/31/31/31/x Rotom of an unwanted nature. I have a Bold Ditto with 31s in HP and Spe. Should I slap on an Everstone and Destiny Knot at this stage, or use Knot + Power Anket to get the 31/x/31/31/31/31 unwanted nature Rotom, then breed with the Bold Ditto with everstone?

Does anyone know the probability that I'll get a baby with a Hidden Ability if BOTH parents have the hidden ability?

I can put this to the test later today, and I'll post my findings here.

Strangely enough, I seem to be having a similar problem/curiousity related to this. It happened when I was breeding Speed Boost Venipede and now it's happening again with Adaptability Corphish.

With the Venipede: With M SB + F SB there seemed to be an

Now, Corphish:

Parents:

Male Adamant Adaptability Corphish @ Everstone, 31/31/31/xx/31/xx

+ Female Hardy Adaptability Corphish @ Destiny Knot, 31/31/31/xx/31/31

Out of 18 Offspring:

12 Adaptability

6 Hyper Cutter/Shell Armor

so, with this sample size, 67% probablity of HA. It may increase as the sample size increases, more testing will have to be done for that.

Obviously to be more accurate the sample size needs to be higher, and then I would need to breed an HA female + non HA male and record the results of the Offspring abilities, which I will do if I get a decent baby male non-HA in this batch. (I'll edit in more later if it leads to anything)

I guess questions worth considering (if they haven't already been answered, sorry if I'm ninja'ing or stepping on your toes Flareon :

Male HA + Female HA (Same species) ---what is the probability of Offspring with HA?

Male Non HA + Female HA (same species) ---what is the probability of Offspring with HA?

Male (Species 1) + Female HA (Species 2) ----what is the probability of Offspring with HA?

Everstone and Destiny Knot ---Do these have any effect on the probability of Offspring with HA?

Ex: Male HA (everstone) +Female HA (destiny knot) compared to

Male HA (destiny knot) + Female HA (everstone) compared to

Male non HA (everstone) + Female HA (destiny knot) compared to

Male non HA (destiny knot) + Female HA (everstone)

Once we have sufficient sample size from each group, we will obviously be able to tell if a certain combination influences the offspring's ability. Again, sorry if some of these questions are already known, but as I am relatively new to breeding they were weighing on my mind, and if there actually are differences (in this Gen) then that would be pretty huge.

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Strangely enough, I seem to be having a similar problem/curiousity related to this. It happened when I was breeding Speed Boost Venipede and now it's happening again with Adaptability Corphish.

With the Venipede: With M SB + F SB there seemed to be an*unusually* high number of swarm/poison points. and many of these rejects happened to be perfect IV spread :( The chance of the mother passing down her ability is 80%, no?

With the Venipede: With M SB + F SB there seemed to be an

Unless I am completely crazy (and perhaps I am) I am pretty sure that, from last gen, the possibility of the female passing down its ability was 60%. So, in the case of a mon with two abilities, the baby would have a 60% chance to inherit the mom's ability, while there is a 40% chance that the other ability is generated instead. For mons with 3 abilities, the percentage changes to 60%/20%/20%. So, your findings on Corphish would hold true.

Im looking at serebii now, this is what they say:

Black 2 & White 2 has changed this. Now, the ability the Pokémon will hatch with is dependant upon the mother. If the mother has their ability in slot 1, then the baby has an

The abilities listed in our Pokédex match the ability order so can be used for reference

Normally, you would be unable to get these abilities through usual breeding. However, if the female Pokémon has the Dream World ability, there is a

So they don't even list the exact percentage of HA passing.

The Gen VI page also doesn't offer any exact numbers:

quote : The most notable change is that Hidden Abilities, which previous required you to have the mother with the Hidden Ability, can now be bred without the mother having it. If the father has got the Hidden Ability, there is a small chance that the offspring will also have their Hidden Ability. However, this only works if you are breeding with a Ditto. This is even more useful considering Hidden Abilities are more easily found via Hordes and Friend Safari.

this is all they offer and to my knowledge this is a generally known fact now.

Scanning the google results, Im seeing results from 25%, to 60% to 80% to 20%, but can Neoseeker and askYahoo really be trusted? I confused :S

edit: and maybe Serebii's High Chance = 60% , it's not that I dont take your word farranpoison , lol, I just need to do some more tests I suppose , lol

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hmm then that would really explain things...

Im looking at serebii now, this is what they say:

**Standard Abilities**

Black 2 & White 2 has changed this. Now, the ability the Pokémon will hatch with is dependant upon the mother. If the mother has their ability in slot 1, then the baby has an**80% chance** of hatching with that ability, and 20% for the second ability and viceversa if the mother has the ability in the second slot. This calculation even happens if the baby Pokémon or the moth only has one ability, since the ability is the same in both slots. For example, if you are breeding a female Pidgeot and it has the ability of Tangled Feet, the baby Pidgey will have an 80% chance of having the ability Tangled Feet and a 20% chance of having Keen Eye.

The abilities listed in our Pokédex match the ability order so can be used for reference

**Hidden Abilities**

Normally, you would be unable to get these abilities through usual breeding. However, if the female Pokémon has the Dream World ability, there is a**high chance** that the ability of the offspring will be the ability it has listed for Dream World abilities. However, if the male Pokémon has the Dream World ability and the female doesn't, and if you breed the female with a Ditto, the Pokémon will definitely not get the Dream World ability.

So they don't even list the exact percentage of HA passing.

The Gen VI page also doesn't offer any exact numbers

Im looking at serebii now, this is what they say:

Black 2 & White 2 has changed this. Now, the ability the Pokémon will hatch with is dependant upon the mother. If the mother has their ability in slot 1, then the baby has an

The abilities listed in our Pokédex match the ability order so can be used for reference

Normally, you would be unable to get these abilities through usual breeding. However, if the female Pokémon has the Dream World ability, there is a

So they don't even list the exact percentage of HA passing.

The Gen VI page also doesn't offer any exact numbers

Sorry for the double, but this is pretty long and on a slightly different topic, so...

I haven’t seen any statistics of this matter, so I figured I’d go ahead and post, since this may be useful for newcomer breeders such as myself.

**Going from 4IV + 5IV mon to 5IV mon**

Parents: Male HA 31/31/31/xx/31/xx @ Everstone

Female HA 31/31/31/xx/31/31 @ Destiny Knot

Goal: 31/31/31/xx/31/31

Sample Size= 18

**HA:**

1236

1235

1236

12356 **

1235

1236

135

1235

125

135

12356 **

2356

**Non HA:**

12356 **

2356

235

125

1235

235

Probability of :

31/31/31/xx/31/31 (disregard Ability) =3/18=1/6=**17% **

4 Perfect IV’s (disregard Ability) = 9/18 =1/2 =**50%**

3 Perfect IV’s (disregard Ability) =6/18 = 1/3 =**33%**

31/31/31/xx/31/31 (HA) = 2/18 =1/9 =**11%**

4 Perfect IV’s (HA) = 7/18=**39%**

3 Perfect IV’s (HA) = 3/18 =**17%**

The other**33%** is occupied by Non HA

Probability that, out of HA’s, you will get 31/31/31/xx/31/31 =2/12=**16.7 %**

I guess the most important stat of this is knowing that if you are trying to go from a 4IV mon + 5IV mon, there is an**11%** chance , or 1 out of every 9, that you will get your desired spread. I think this helps me to see, that when I am trying to move up the breeding ladder, it is statistically certain that I will see a set amount of 5IV’d mons, and that if I check 12 mons and somehow it is no dice, that it is probable there will be 2 or 3 5IV’d mons in the last batch.

Note: Out of the 3 good 5IV spreads, two were female HA, one was Male non HA. I was in luck, since all i needed was a 5IV Male, but if you are looking for a certain gender/ability it may take more than 18 eggs to hatch.

Gender Ratio (.5 for Corphish)* HA Probability(.6)=.3= 30% chance you will find the correct Gender/Ability Spread out of your 5 IV’d mons.

I do not know how these percentages would translate given a ~100 mon sample size.

**Going from 5IV + 5IV mon to 5IV mon**

Parents: Male non HA 31/31/31/xx/31/31 @ Everstone

Female HA 31/31/31/xx/31/31 @ Destiny Knot

Goal: 31/31/31/xx/31/31

(I took into account the factor that whether or not the Male is HA is irrelevant)

Sample Size=18

**HA (10):**

2356

1356

2356

12356 **

12356 **

1356

2356

1256

1256

1256

**Non HA (8)**

1235

1235

1256

1236

12356 **

2356

1236

1235

Probability of :

31/31/31/xx/31/31 (disregard Ability) =3/18=**17%**

only 4 Perfect IV’s (disregard Ability) =15/18=**83%**

only 3 Perfect IV’s (disregard Ability) = 0

31/31/31/xx/31/31 (HA) = 2/18=**11%**

only 4 Perfect IV’s (HA) = 16/18=**89%**

only 3 Perfect IV’s (HA) = 0

Probability that, out of HA’s, you will get 31/31/31/xx/31/31 : 2/10=**20%**

The interesting thing here is that, whether you go 4+5IV or 5+5IV, your probability of getting the correct 5IV spread (31/31/31/xx/31/31)**is exactly the same. ** I was surprised to find this out, as I was sure that the probability would be higher with two 5IV mons.

The discrepancy between this:

(4+5IV to 5IV) Probability that, out of HA’s, you will get 31/31/31/xx/31/31 =2/12=**16.7 %**

(5+5IV to 5IV) Probability that, out of HA’s, you will get 31/31/31/xx/31/31 : 2/10=**20%**

is likely only due to low sample size.

**These findings surely save time** by realizing that there is no need to replace your 5+4IV’d mon with another 5IV’d mon, unless you want generally higher IV’s for spitback trading or wondertrading.

Again, I am surprised by this, and if anyone can point out why the probability of getting a correct 5IV spread is the same in both instances, I would be very glad to know.

Regardless, It looks like there is an ~11% chance of both passing down the hidden ability AND getting the correct 5IV spread. I wonder, since the Destiny Knot guarantees 5 IV's to pass down , if the percentage isn't actually closer to 1/6 = 16.7%. (haha, yes actually, it is, if you are taking into account all abilities :D), but, 60%(HA rate)*16.7% actually equals 10%, which is very close to 11%, so I wouldn't be surprised to find that this is directly correlated to my manual findings, whose 11% would most likely approach 10 as the sample size approached 100. Edit: I can guess atm that these percentages pass on the the next higher tiers , being a 6IV'd mon + 5 IV'd mon, and a 6IV'd mon + another 6IV'd mon.

**tl;dr : **

The chances of hatching a 31/31/31/xx/31/31 HA mon from 31/31/31/xx/31/31 + 31/31/31/xx/31/xx HA parents is 10%

The chances of hatching a 31/31/31/xx/31/31 HA mon from 31/31/31/xx/31/31 HA parents is 10%

Simple math: 16.7%(chance of Destiny Knot choosing the right stats to pass down) * 60% (chance of Female HA passing down HA) = 10%

Edit: After looking at some stuff about permutations and combinations, I am really unsure as to whether I did this math right. Confirmation or Dissension would be highly appreciated.

I haven’t seen any statistics of this matter, so I figured I’d go ahead and post, since this may be useful for newcomer breeders such as myself.

Parents: Male HA 31/31/31/xx/31/xx @ Everstone

Female HA 31/31/31/xx/31/31 @ Destiny Knot

Goal: 31/31/31/xx/31/31

Sample Size= 18

1236

1235

1236

12356 **

1235

1236

135

1235

125

135

12356 **

2356

12356 **

2356

235

125

1235

235

Probability of :

31/31/31/xx/31/31 (disregard Ability) =3/18=1/6=

4 Perfect IV’s (disregard Ability) = 9/18 =1/2 =

3 Perfect IV’s (disregard Ability) =6/18 = 1/3 =

31/31/31/xx/31/31 (HA) = 2/18 =1/9 =

4 Perfect IV’s (HA) = 7/18=

3 Perfect IV’s (HA) = 3/18 =

The other

Probability that, out of HA’s, you will get 31/31/31/xx/31/31 =2/12=

I guess the most important stat of this is knowing that if you are trying to go from a 4IV mon + 5IV mon, there is an

Note: Out of the 3 good 5IV spreads, two were female HA, one was Male non HA. I was in luck, since all i needed was a 5IV Male, but if you are looking for a certain gender/ability it may take more than 18 eggs to hatch.

Gender Ratio (.5 for Corphish)* HA Probability(.6)=.3= 30% chance you will find the correct Gender/Ability Spread out of your 5 IV’d mons.

I do not know how these percentages would translate given a ~100 mon sample size.

Parents: Male non HA 31/31/31/xx/31/31 @ Everstone

Female HA 31/31/31/xx/31/31 @ Destiny Knot

Goal: 31/31/31/xx/31/31

(I took into account the factor that whether or not the Male is HA is irrelevant)

Sample Size=18

2356

1356

2356

12356 **

12356 **

1356

2356

1256

1256

1256

1235

1235

1256

1236

12356 **

2356

1236

1235

Probability of :

31/31/31/xx/31/31 (disregard Ability) =3/18=

only 4 Perfect IV’s (disregard Ability) =15/18=

only 3 Perfect IV’s (disregard Ability) = 0

31/31/31/xx/31/31 (HA) = 2/18=

only 4 Perfect IV’s (HA) = 16/18=

only 3 Perfect IV’s (HA) = 0

Probability that, out of HA’s, you will get 31/31/31/xx/31/31 : 2/10=

The interesting thing here is that, whether you go 4+5IV or 5+5IV, your probability of getting the correct 5IV spread (31/31/31/xx/31/31)

The discrepancy between this:

(4+5IV to 5IV) Probability that, out of HA’s, you will get 31/31/31/xx/31/31 =2/12=

(5+5IV to 5IV) Probability that, out of HA’s, you will get 31/31/31/xx/31/31 : 2/10=

is likely only due to low sample size.

Again, I am surprised by this, and if anyone can point out why the probability of getting a correct 5IV spread is the same in both instances, I would be very glad to know.

Regardless, It looks like there is an ~11% chance of both passing down the hidden ability AND getting the correct 5IV spread. I wonder, since the Destiny Knot guarantees 5 IV's to pass down , if the percentage isn't actually closer to 1/6 = 16.7%. (haha, yes actually, it is, if you are taking into account all abilities :D), but, 60%(HA rate)*16.7% actually equals 10%, which is very close to 11%, so I wouldn't be surprised to find that this is directly correlated to my manual findings, whose 11% would most likely approach 10 as the sample size approached 100. Edit: I can guess atm that these percentages pass on the the next higher tiers , being a 6IV'd mon + 5 IV'd mon, and a 6IV'd mon + another 6IV'd mon.

The chances of hatching a 31/31/31/xx/31/31 HA mon from 31/31/31/xx/31/31 + 31/31/31/xx/31/xx HA parents is 10%

The chances of hatching a 31/31/31/xx/31/31 HA mon from 31/31/31/xx/31/31 HA parents is 10%

Simple math: 16.7%(chance of Destiny Knot choosing the right stats to pass down) * 60% (chance of Female HA passing down HA) = 10%

Edit: After looking at some stuff about permutations and combinations, I am really unsure as to whether I did this math right. Confirmation or Dissension would be highly appreciated.

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Ok thanks. I think I'm gonna go back Safari and do some mass Ditto hunting after this. Until I can bring my RNG Dittos over.

6 + 6 will have 1/32 chance that may get perfect 31 but what about 5 + 6 chance?

are you talking about if the 6th random stat will be chosen as 31?

See, at first I thought that the probability that ANY random stat would be chosen as 31 would be 1/32, so the probability that you would get it in the 6th stat, if you have 31/31/31/xx/31/31 parents, or even if you have a 6+6, would be 1/32 * 1/6 = 1/192 = .5%

With a 5 + 6, (31/31/31/xx/31/31 + 31/31/31/31/31), I think the probability would be the same, simply because the Destiny Knot could choose the 5 perfect IV's and you would still have to rely on RNG to give you that sixth stat.

EDIT: Actually, the destiny knot *could* choose the xx stat. I guess there would be a 1/12 chance of this. Or an 11/12 chance that it would choose the right ones. So the probability that the Destiny Knot would choose the right stats AND the that the 6th random would be 31 would be:

11/12 (chance that the DK chooses the right stats) * 1/6(chance that the correct 6th stat is chosen * 1/32(chance that 31 IV is chosen) Which would come to: 11/2304 or .47%

BUT

after reading about combinations and permutations, which I would assume would come into play given that the Destiny Knot chooses a set of 5, I am very unsure of this! Hopefully I will get around to learning more about this, or somebody who does know this math will enlighten us!

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For anybody wondering about breeding mechanics, this would be the thread to go to:

Breeding Perfect Pokemon in Pokemon X&Y